5x^2+48+27=0

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Solution for 5x^2+48+27=0 equation: 



5x^2+48+27=0

We add all the numbers together, and all the variables

5x^2+75=0

a = 5; b = 0; c = +75;
Δ = b2-4ac
Δ = 02-4·5·75
Δ = -1500
Delta is less than zero, so there is no solution for the equation

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